Base | Representation |
---|---|
bin | 11101111000011010110010… |
… | …100100111100111000111100 |
3 | 122020022200001000021110201011 |
4 | 131320122302210330320330 |
5 | 114211142442232312134 |
6 | 1143301411210125004 |
7 | 36452545105046602 |
oct | 3570326244747074 |
9 | 566280030243634 |
10 | 131420405354044 |
11 | 38969098776a84 |
12 | 128a61a3a20764 |
13 | 5843b77831241 |
14 | 2464ad2849872 |
15 | 102d82dd44264 |
hex | 7786b293ce3c |
131420405354044 has 12 divisors (see below), whose sum is σ = 230060404327600. Its totient is φ = 65688861260448.
The previous prime is 131420405354039. The next prime is 131420405354083. The reversal of 131420405354044 is 440453504024131.
It is a junction number, because it is equal to n+sod(n) for n = 131420405353988 and 131420405354006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5335340289 + ... + 5335364920.
Almost surely, 2131420405354044 is an apocalyptic number.
It is an amenable number.
131420405354044 is a deficient number, since it is larger than the sum of its proper divisors (98639998973556).
131420405354044 is a wasteful number, since it uses less digits than its factorization.
131420405354044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10670708292 (or 10670708290 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 131420405354044 its reverse (440453504024131), we get a palindrome (571873909378175).
The spelling of 131420405354044 in words is "one hundred thirty-one trillion, four hundred twenty billion, four hundred five million, three hundred fifty-four thousand, forty-four".
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