Base | Representation |
---|---|
bin | 1011111100111101111010… |
… | …1100101000010110100010 |
3 | 1201112100220110002010001221 |
4 | 2333033132230220112202 |
5 | 3210304400021400114 |
6 | 43541212000245254 |
7 | 2524324014026245 |
oct | 277173654502642 |
9 | 51470813063057 |
10 | 13142041200034 |
11 | 420756571070a |
12 | 158302301082a |
13 | 74439b3bb586 |
14 | 33611479525c |
15 | 17bcc46a8524 |
hex | bf3deb285a2 |
13142041200034 has 4 divisors (see below), whose sum is σ = 19713061800054. Its totient is φ = 6571020600016.
The previous prime is 13142041200023. The next prime is 13142041200049. The reversal of 13142041200034 is 43000214024131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7108862400025 + 6033178800009 = 2666245^2 + 2456253^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13142041199981 and 13142041200008.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285510300007 + ... + 3285510300010.
Almost surely, 213142041200034 is an apocalyptic number.
13142041200034 is a deficient number, since it is larger than the sum of its proper divisors (6571020600020).
13142041200034 is an equidigital number, since it uses as much as digits as its factorization.
13142041200034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6571020600019.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13142041200034 its reverse (43000214024131), we get a palindrome (56142255224165).
The spelling of 13142041200034 in words is "thirteen trillion, one hundred forty-two billion, forty-one million, two hundred thousand, thirty-four".
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