13142044130 has 16 divisors (see below), whose sum is σ = 23657892480. Its totient is φ = 5256325872.

The previous prime is 13142044121. The next prime is 13142044133. The reversal of 13142044130 is 3144024131.

It is a junction number, because it is equal to n+sod(n) for n = 13142044096 and 13142044105.

It is not an unprimeable number, because it can be changed into a prime (13142044133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62711 + ... + 173829.

It is an arithmetic number, because the mean of its divisors is an integer number (1478618280).

Almost surely, 2^13142044130 is an apocalyptic number.

13142044130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13142044130 is a deficient number, since it is larger than the sum of its proper divisors (10515848350).

13142044130 is a wasteful number, since it uses less digits than its factorization.

13142044130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122953.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13142044130 its reverse (3144024131), we get a palindrome (16286068261).

The spelling of 13142044130 in words is "thirteen billion, one hundred forty-two million, forty-four thousand, one hundred thirty".