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1314207054895 = 5743873227279
BaseRepresentation
bin10011000111111100110…
…110000011110000101111
311122122012100102121201111
4103013330312003300233
5133012444001224040
62443423254052451
7163643163436450
oct23077466036057
94578170377644
101314207054895
11467396691879
1219285134a127
1396c105907b7
144787235d127
15242bb307dea
hex131fcd83c2f

1314207054895 has 16 divisors (see below), whose sum is σ = 1844256015360. Its totient is φ = 880213096224.

The previous prime is 1314207054893. The next prime is 1314207054911. The reversal of 1314207054895 is 5984507024131.

It is a happy number.

It is not a de Polignac number, because 1314207054895 - 21 = 1314207054893 is a prime.

It is a super-2 number, since 2×13142070548952 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314207054893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 436612135 + ... + 436615144.

It is an arithmetic number, because the mean of its divisors is an integer number (115266000960).

Almost surely, 21314207054895 is an apocalyptic number.

1314207054895 is a deficient number, since it is larger than the sum of its proper divisors (530048960465).

1314207054895 is an equidigital number, since it uses as much as digits as its factorization.

1314207054895 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 873227334.

The product of its (nonzero) digits is 1209600, while the sum is 49.

The spelling of 1314207054895 in words is "one trillion, three hundred fourteen billion, two hundred seven million, fifty-four thousand, eight hundred ninety-five".

Divisors: 1 5 7 35 43 215 301 1505 873227279 4366136395 6112590953 30562954765 37548772997 187743864985 262841410979 1314207054895