Base | Representation |
---|---|
bin | 1011111100111110100110… |
… | …1000000100010100010001 |
3 | 1201112101101020002102101011 |
4 | 2333033221220010110101 |
5 | 3210310233441200413 |
6 | 43541242110210521 |
7 | 2524331401351546 |
oct | 277175150042421 |
9 | 51471336072334 |
10 | 13142224553233 |
11 | 420764a163686 |
12 | 15830744b3a41 |
13 | 7443ca3977a9 |
14 | 336130c82bcd |
15 | 17bcd582533d |
hex | bf3e9a04511 |
13142224553233 has 2 divisors, whose sum is σ = 13142224553234. Its totient is φ = 13142224553232.
The previous prime is 13142224553219. The next prime is 13142224553239. The reversal of 13142224553233 is 33235542224131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9769169071489 + 3373055481744 = 3125567^2 + 1836588^2 .
It is a cyclic number.
It is not a de Polignac number, because 13142224553233 - 221 = 13142222456081 is a prime.
It is not a weakly prime, because it can be changed into another prime (13142224553239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571112276616 + 6571112276617.
It is an arithmetic number, because the mean of its divisors is an integer number (6571112276617).
Almost surely, 213142224553233 is an apocalyptic number.
It is an amenable number.
13142224553233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142224553233 is an equidigital number, since it uses as much as digits as its factorization.
13142224553233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 518400, while the sum is 40.
Adding to 13142224553233 its reverse (33235542224131), we get a palindrome (46377766777364).
The spelling of 13142224553233 in words is "thirteen trillion, one hundred forty-two billion, two hundred twenty-four million, five hundred fifty-three thousand, two hundred thirty-three".
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