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131422335034451 is a prime number
BaseRepresentation
bin11101111000011100100101…
…100110000110010001010011
3122020022212000111022101120212
4131320130211212012101103
5114211210420232100301
61143302330501554335
736452643656054156
oct3570344546062123
9566285014271525
10131422335034451
1138969998a5447a
12128a66421159ab
1358440c4557476
142464c36c3bc9d
15102d8e34664bb
hex778725986453

131422335034451 has 2 divisors, whose sum is σ = 131422335034452. Its totient is φ = 131422335034450.

The previous prime is 131422335034387. The next prime is 131422335034457. The reversal of 131422335034451 is 154430533224131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131422335034451 - 26 = 131422335034387 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131422335034399 and 131422335034408.

It is not a weakly prime, because it can be changed into another prime (131422335034457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711167517225 + 65711167517226.

It is an arithmetic number, because the mean of its divisors is an integer number (65711167517226).

Almost surely, 2131422335034451 is an apocalyptic number.

131422335034451 is a deficient number, since it is larger than the sum of its proper divisors (1).

131422335034451 is an equidigital number, since it uses as much as digits as its factorization.

131422335034451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 131422335034451 its reverse (154430533224131), we get a palindrome (285852868258582).

The spelling of 131422335034451 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, three hundred thirty-five million, thirty-four thousand, four hundred fifty-one".