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131423114406401 is a prime number
BaseRepresentation
bin11101111000011101010100…
…000011001010101000000001
3122020022221000210211120220122
4131320131110003022220001
5114211214014242001101
61143302540102350025
736453002201444456
oct3570352403125001
9566287023746818
10131423114406401
113896a258986124
12128a681b12b315
1358441b9b670bc
142464cac55782d
15102d93bab651b
hex7787540caa01

131423114406401 has 2 divisors, whose sum is σ = 131423114406402. Its totient is φ = 131423114406400.

The previous prime is 131423114406359. The next prime is 131423114406433. The reversal of 131423114406401 is 104604411324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123601029760000 + 7822084646401 = 11117600^2 + 2796799^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131423114406401 is a prime.

It is not a weakly prime, because it can be changed into another prime (131423114436401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711557203200 + 65711557203201.

It is an arithmetic number, because the mean of its divisors is an integer number (65711557203201).

Almost surely, 2131423114406401 is an apocalyptic number.

It is an amenable number.

131423114406401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423114406401 is an equidigital number, since it uses as much as digits as its factorization.

131423114406401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 131423114406401 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred fourteen million, four hundred six thousand, four hundred one".