Base | Representation |
---|---|
bin | 11101111000011101010101… |
… | …000011110000110110101011 |
3 | 122020022221001222200220201111 |
4 | 131320131111003300312223 |
5 | 114211214033110341303 |
6 | 1143302541505331151 |
7 | 36453002465413243 |
oct | 3570352503606653 |
9 | 566287058626644 |
10 | 131423131340203 |
11 | 3896a2674a17aa |
12 | 128a6824936ab7 |
13 | 58441c05159c1 |
14 | 2464cb08c4b23 |
15 | 102d93d30db6d |
hex | 7787550f0dab |
131423131340203 has 2 divisors, whose sum is σ = 131423131340204. Its totient is φ = 131423131340202.
The previous prime is 131423131340167. The next prime is 131423131340231. The reversal of 131423131340203 is 302043131324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131423131340203 - 229 = 131422594469291 is a prime.
It is not a weakly prime, because it can be changed into another prime (131423131349203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711565670101 + 65711565670102.
It is an arithmetic number, because the mean of its divisors is an integer number (65711565670102).
Almost surely, 2131423131340203 is an apocalyptic number.
131423131340203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423131340203 is an equidigital number, since it uses as much as digits as its factorization.
131423131340203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131423131340203 its reverse (302043131324131), we get a palindrome (433466262664334).
The spelling of 131423131340203 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, three hundred forty thousand, two hundred three".
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