Base | Representation |
---|---|
bin | 10011000111111110011… |
… | …100110110101101011011 |
3 | 11122122021020010200120022 |
4 | 103013332130312231123 |
5 | 133013022401033032 |
6 | 2443430055421055 |
7 | 163643641462304 |
oct | 23077634665533 |
9 | 4578236120508 |
10 | 1314234002267 |
11 | 4673aa91782a |
12 | 19285a38478b |
13 | 96c160371a4 |
14 | 47875b757ab |
15 | 242bd87c512 |
hex | 131fe736b5b |
1314234002267 has 2 divisors, whose sum is σ = 1314234002268. Its totient is φ = 1314234002266.
The previous prime is 1314234002203. The next prime is 1314234002281. The reversal of 1314234002267 is 7622004324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314234002267 - 26 = 1314234002203 is a prime.
It is a super-2 number, since 2×13142340022672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314234002297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657117001133 + 657117001134.
It is an arithmetic number, because the mean of its divisors is an integer number (657117001134).
Almost surely, 21314234002267 is an apocalyptic number.
1314234002267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314234002267 is an equidigital number, since it uses as much as digits as its factorization.
1314234002267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 1314234002267 its reverse (7622004324131), we get a palindrome (8936238326398).
The spelling of 1314234002267 in words is "one trillion, three hundred fourteen billion, two hundred thirty-four million, two thousand, two hundred sixty-seven".
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