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13142341441601 is a prime number
BaseRepresentation
bin1011111100111111000010…
…0101111101100001000001
31201112101200101000222001222
42333033300211331201001
53210311003402112401
643541301443404425
72524334321033141
oct277176045754101
951471611028058
1013142341441601
1142076aa13a639
1215830a7683715
137444186722c8
143361425cc921
1517bce0c13c1b
hexbf3f097d841

13142341441601 has 2 divisors, whose sum is σ = 13142341441602. Its totient is φ = 13142341441600.

The previous prime is 13142341441553. The next prime is 13142341441687. The reversal of 13142341441601 is 10614414324131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8287374288400 + 4854967153201 = 2878780^2 + 2203399^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142341441601 - 234 = 13125161572417 is a prime.

It is a super-2 number, since 2×131423414416012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13142341443601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571170720800 + 6571170720801.

It is an arithmetic number, because the mean of its divisors is an integer number (6571170720801).

Almost surely, 213142341441601 is an apocalyptic number.

It is an amenable number.

13142341441601 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142341441601 is an equidigital number, since it uses as much as digits as its factorization.

13142341441601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 13142341441601 its reverse (10614414324131), we get a palindrome (23756755765732).

The spelling of 13142341441601 in words is "thirteen trillion, one hundred forty-two billion, three hundred forty-one million, four hundred forty-one thousand, six hundred one".