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131423421311242 = 266599868104919
BaseRepresentation
bin11101111000011101100110…
…010101111010100100001010
3122020022221211012022222012121
4131320131212111322210022
5114211220131323424432
61143303030344401454
736453012616212664
oct3570354625724412
9566287735288177
10131423421311242
113896a3a6146295
12128a68a5a7628a
1358442386119b8
142464cdb207534
15102d9589db197
hex77876657a90a

131423421311242 has 8 divisors (see below), whose sum is σ = 197164736301600. Its totient is φ = 65701842544044.

The previous prime is 131423421311227. The next prime is 131423421311261. The reversal of 131423421311242 is 242113124324131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131423421311198 and 131423421311207.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4934039142 + ... + 4934065777.

It is an arithmetic number, because the mean of its divisors is an integer number (24645592037700).

Almost surely, 2131423421311242 is an apocalyptic number.

131423421311242 is a deficient number, since it is larger than the sum of its proper divisors (65741314990358).

131423421311242 is an equidigital number, since it uses as much as digits as its factorization.

131423421311242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9868111580.

The product of its digits is 27648, while the sum is 34.

Adding to 131423421311242 its reverse (242113124324131), we get a palindrome (373536545635373).

The spelling of 131423421311242 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, four hundred twenty-one million, three hundred eleven thousand, two hundred forty-two".

Divisors: 1 2 6659 13318 9868104919 19736209838 65711710655621 131423421311242