Base | Representation |
---|---|
bin | 11101111000011101101100… |
… | …010110000011110101111101 |
3 | 122020022222002012211010102100 |
4 | 131320131230112003311331 |
5 | 114211220333113400131 |
6 | 1143303044343015313 |
7 | 36453015251155533 |
oct | 3570355426036575 |
9 | 566288065733370 |
10 | 131423522012541 |
11 | 3896a447a76700 |
12 | 128a691373a539 |
13 | 584425343c775 |
14 | 2464d0a73c153 |
15 | 102d96277d7e6 |
hex | 77876c583d7d |
131423522012541 has 144 divisors (see below), whose sum is σ = 214842246877440. Its totient is φ = 77319706464000.
The previous prime is 131423522012521. The next prime is 131423522012561. The reversal of 131423522012541 is 145210225324131.
131423522012541 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 2 + 3 + 522 + 0 + 125 + 4 + 1 = 666.
It is an interprime number because it is at equal distance from previous prime (131423522012521) and next prime (131423522012561).
It is not a de Polignac number, because 131423522012541 - 25 = 131423522012509 is a prime.
It is a super-2 number, since 2×1314235220125412 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131423522012496 and 131423522012505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131423522012501) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 7776071191 + ... + 7776088091.
It is an arithmetic number, because the mean of its divisors is an integer number (1491960047760).
Almost surely, 2131423522012541 is an apocalyptic number.
131423522012541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131423522012541 is a deficient number, since it is larger than the sum of its proper divisors (83418724864899).
131423522012541 is a wasteful number, since it uses less digits than its factorization.
131423522012541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18208 (or 18194 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 131423522012541 its reverse (145210225324131), we get a palindrome (276633747336672).
The spelling of 131423522012541 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, five hundred twenty-two million, twelve thousand, five hundred forty-one".
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