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1314240112547 is a prime number
BaseRepresentation
bin10011000111111110110…
…100001010011110100011
311122122021122122010021222
4103013332310022132203
5133013030432100142
62443430434405255
7163644044431445
oct23077664123643
94578248563258
101314240112547
1146740331054a
1219286043082b
1396c1739643b
14478768c6495
15242be187bd2
hex131fed0a7a3

1314240112547 has 2 divisors, whose sum is σ = 1314240112548. Its totient is φ = 1314240112546.

The previous prime is 1314240112463. The next prime is 1314240112573. The reversal of 1314240112547 is 7452110424131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1314240112547 - 210 = 1314240111523 is a prime.

It is not a weakly prime, because it can be changed into another prime (1314240112847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657120056273 + 657120056274.

It is an arithmetic number, because the mean of its divisors is an integer number (657120056274).

Almost surely, 21314240112547 is an apocalyptic number.

1314240112547 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314240112547 is an equidigital number, since it uses as much as digits as its factorization.

1314240112547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 1314240112547 its reverse (7452110424131), we get a palindrome (8766350536678).

The spelling of 1314240112547 in words is "one trillion, three hundred fourteen billion, two hundred forty million, one hundred twelve thousand, five hundred forty-seven".