Base | Representation |
---|---|
bin | 10011000111111110110… |
… | …100001010011110100011 |
3 | 11122122021122122010021222 |
4 | 103013332310022132203 |
5 | 133013030432100142 |
6 | 2443430434405255 |
7 | 163644044431445 |
oct | 23077664123643 |
9 | 4578248563258 |
10 | 1314240112547 |
11 | 46740331054a |
12 | 19286043082b |
13 | 96c1739643b |
14 | 478768c6495 |
15 | 242be187bd2 |
hex | 131fed0a7a3 |
1314240112547 has 2 divisors, whose sum is σ = 1314240112548. Its totient is φ = 1314240112546.
The previous prime is 1314240112463. The next prime is 1314240112573. The reversal of 1314240112547 is 7452110424131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314240112547 - 210 = 1314240111523 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314240112847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657120056273 + 657120056274.
It is an arithmetic number, because the mean of its divisors is an integer number (657120056274).
Almost surely, 21314240112547 is an apocalyptic number.
1314240112547 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314240112547 is an equidigital number, since it uses as much as digits as its factorization.
1314240112547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 1314240112547 its reverse (7452110424131), we get a palindrome (8766350536678).
The spelling of 1314240112547 in words is "one trillion, three hundred fourteen billion, two hundred forty million, one hundred twelve thousand, five hundred forty-seven".
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