Base | Representation |
---|---|
bin | 10011000111111110110… |
… | …111100101111011001001 |
3 | 11122122021201022210021212 |
4 | 103013332313211323021 |
5 | 133013031144331101 |
6 | 2443430505542505 |
7 | 163644055164143 |
oct | 23077667457311 |
9 | 4578251283255 |
10 | 1314241011401 |
11 | 4674038748aa |
12 | 1928607a4a35 |
13 | 96c1761c5c6 |
14 | 47876a7bc93 |
15 | 242be2b41bb |
hex | 131fede5ec9 |
1314241011401 has 2 divisors, whose sum is σ = 1314241011402. Its totient is φ = 1314241011400.
The previous prime is 1314241011383. The next prime is 1314241011409. The reversal of 1314241011401 is 1041101424131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 973300633600 + 340940377801 = 986560^2 + 583901^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314241011401 - 26 = 1314241011337 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314241011409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657120505700 + 657120505701.
It is an arithmetic number, because the mean of its divisors is an integer number (657120505701).
Almost surely, 21314241011401 is an apocalyptic number.
It is an amenable number.
1314241011401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314241011401 is an equidigital number, since it uses as much as digits as its factorization.
1314241011401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1314241011401 its reverse (1041101424131), we get a palindrome (2355342435532).
The spelling of 1314241011401 in words is "one trillion, three hundred fourteen billion, two hundred forty-one million, eleven thousand, four hundred one".
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