Base | Representation |
---|---|
bin | 11101111000011110010100… |
… | …111011110101000111011101 |
3 | 122020100000211200012222210111 |
4 | 131320132110323311013131 |
5 | 114211223231432033313 |
6 | 1143303240111010021 |
7 | 36453041160402523 |
oct | 3570362473650735 |
9 | 566300750188714 |
10 | 131424203002333 |
11 | 3896a76741138a |
12 | 128a6a83809911 |
13 | 58443315540c7 |
14 | 2464d72d68313 |
15 | 102d9a244843d |
hex | 778794ef51dd |
131424203002333 has 8 divisors (see below), whose sum is σ = 131464388646720. Its totient is φ = 131384022279840.
The previous prime is 131424203002249. The next prime is 131424203002357. The reversal of 131424203002333 is 333200302424131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131424203002333 - 213 = 131424202994141 is a prime.
It is a super-2 number, since 2×1314242030023332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131424203002295 and 131424203002304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131424203006333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52540278 + ... + 54984808.
It is an arithmetic number, because the mean of its divisors is an integer number (16433048580840).
Almost surely, 2131424203002333 is an apocalyptic number.
It is an amenable number.
131424203002333 is a deficient number, since it is larger than the sum of its proper divisors (40185644387).
131424203002333 is a wasteful number, since it uses less digits than its factorization.
131424203002333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2460947.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 131424203002333 its reverse (333200302424131), we get a palindrome (464624505426464).
The spelling of 131424203002333 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred three million, two thousand, three hundred thirty-three".
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