Base | Representation |
---|---|
bin | 11101111000011110010101… |
… | …011011111101010001000011 |
3 | 122020100000212021001212121001 |
4 | 131320132111123331101003 |
5 | 114211223241111034243 |
6 | 1143303241011312431 |
7 | 36453041322110446 |
oct | 3570362533752103 |
9 | 566300767055531 |
10 | 131424211424323 |
11 | 3896a771143a04 |
12 | 128a6a865ab717 |
13 | 584433321262c |
14 | 2464d7411b65d |
15 | 102d9a305da4d |
hex | 7787956fd443 |
131424211424323 has 2 divisors, whose sum is σ = 131424211424324. Its totient is φ = 131424211424322.
The previous prime is 131424211424293. The next prime is 131424211424357. The reversal of 131424211424323 is 323424112424131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131424211424323 - 29 = 131424211423811 is a prime.
It is not a weakly prime, because it can be changed into another prime (131424211425323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712105712161 + 65712105712162.
It is an arithmetic number, because the mean of its divisors is an integer number (65712105712162).
Almost surely, 2131424211424323 is an apocalyptic number.
131424211424323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131424211424323 is an equidigital number, since it uses as much as digits as its factorization.
131424211424323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 37.
Adding to 131424211424323 its reverse (323424112424131), we get a palindrome (454848323848454).
The spelling of 131424211424323 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred eleven million, four hundred twenty-four thousand, three hundred twenty-three".
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