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131424511320001 is a prime number
BaseRepresentation
bin11101111000011110100111…
…010011111101111111000001
3122020100001122011101011010101
4131320132213103331333001
5114211224344344220001
61143303330443202401
736453051623144044
oct3570364723757701
9566301564334111
10131424511320001
113896a905456a79
12128a6b4ab16401
1358443803a4ab3
142464da1ca4c5b
15102d9be54ba01
hex7787a74fdfc1

131424511320001 has 2 divisors, whose sum is σ = 131424511320002. Its totient is φ = 131424511320000.

The previous prime is 131424511319993. The next prime is 131424511320017. The reversal of 131424511320001 is 100023115424131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114670879985601 + 16753631334400 = 10708449^2 + 4093120^2 .

It is a cyclic number.

It is not a de Polignac number, because 131424511320001 - 23 = 131424511319993 is a prime.

It is not a weakly prime, because it can be changed into another prime (131424511320031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712255660000 + 65712255660001.

It is an arithmetic number, because the mean of its divisors is an integer number (65712255660001).

Almost surely, 2131424511320001 is an apocalyptic number.

It is an amenable number.

131424511320001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131424511320001 is an equidigital number, since it uses as much as digits as its factorization.

131424511320001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 131424511320001 its reverse (100023115424131), we get a palindrome (231447626744132).

The spelling of 131424511320001 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, five hundred eleven million, three hundred twenty thousand, one".