Base | Representation |
---|---|
bin | 1011111100111111101011… |
… | …0101010111110000111011 |
3 | 1201112102010100022220121020 |
4 | 2333033322311113300323 |
5 | 3210311331343102220 |
6 | 43541330502113523 |
7 | 2524341505306236 |
oct | 277177265276073 |
9 | 51472110286536 |
10 | 13142513253435 |
11 | 420778811a395 |
12 | 158313511b8a3 |
13 | 74444513a207 |
14 | 33615b35441d |
15 | 17bd00d51040 |
hex | bf3fad57c3b |
13142513253435 has 64 divisors (see below), whose sum is σ = 22365851397120. Its totient is φ = 6571117854720.
The previous prime is 13142513253431. The next prime is 13142513253497. The reversal of 13142513253435 is 53435231524131.
It is not a de Polignac number, because 13142513253435 - 22 = 13142513253431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13142513253431) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 249912154 + ... + 249964736.
It is an arithmetic number, because the mean of its divisors is an integer number (349466428080).
Almost surely, 213142513253435 is an apocalyptic number.
13142513253435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13142513253435 is a deficient number, since it is larger than the sum of its proper divisors (9223338143685).
13142513253435 is a wasteful number, since it uses less digits than its factorization.
13142513253435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61748.
The product of its digits is 648000, while the sum is 42.
Adding to 13142513253435 its reverse (53435231524131), we get a palindrome (66577744777566).
The spelling of 13142513253435 in words is "thirteen trillion, one hundred forty-two billion, five hundred thirteen million, two hundred fifty-three thousand, four hundred thirty-five".
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