Base | Representation |
---|---|
bin | 111101001100110100… |
… | …0010111010001010111 |
3 | 110120020100011122221221 |
4 | 1322121220113101113 |
5 | 4123130141422012 |
6 | 140213154151211 |
7 | 12331604636215 |
oct | 1723150272127 |
9 | 416210148857 |
10 | 131426514007 |
11 | 50812928228 |
12 | 2157a582507 |
13 | c5165a7669 |
14 | 650ab1dcb5 |
15 | 36431e4507 |
hex | 1e99a17457 |
131426514007 has 4 divisors (see below), whose sum is σ = 132461368576. Its totient is φ = 130391659440.
The previous prime is 131426514001. The next prime is 131426514013. The reversal of 131426514007 is 700415624131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131426514001) and next prime (131426514013).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131426514007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131426514001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 517427094 + ... + 517427347.
It is an arithmetic number, because the mean of its divisors is an integer number (33115342144).
Almost surely, 2131426514007 is an apocalyptic number.
131426514007 is a deficient number, since it is larger than the sum of its proper divisors (1034854569).
131426514007 is a wasteful number, since it uses less digits than its factorization.
131426514007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1034854568.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 131426514007 in words is "one hundred thirty-one billion, four hundred twenty-six million, five hundred fourteen thousand, seven".
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