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1314267279720 = 2335237917093527
BaseRepresentation
bin10011001000000000011…
…011110011000101101000
311122122100112202100122120
4103020000123303011220
5133013104410422340
62443433244551240
7163644524361153
oct23100033630550
94578315670576
101314267279720
1146741768665a
12192869552520
1396c1cbb8ba5
144787a358c9a
15242c17524d0
hex132006f3168

1314267279720 has 256 divisors, whose sum is σ = 4169926656000. Its totient is φ = 330702468096.

The previous prime is 1314267279719. The next prime is 1314267279733. The reversal of 1314267279720 is 279727624131.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 372628597 + ... + 372632123.

It is an arithmetic number, because the mean of its divisors is an integer number (16288776000).

Almost surely, 21314267279720 is an apocalyptic number.

1314267279720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1314267279720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2084963328000).

1314267279720 is an abundant number, since it is smaller than the sum of its proper divisors (2855659376280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314267279720 is a wasteful number, since it uses less digits than its factorization.

1314267279720 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5352 (or 5348 counting only the distinct ones).

The product of its (nonzero) digits is 1778112, while the sum is 51.

The spelling of 1314267279720 in words is "one trillion, three hundred fourteen billion, two hundred sixty-seven million, two hundred seventy-nine thousand, seven hundred twenty".