Base | Representation |
---|---|
bin | 10011001000000011000… |
… | …111110000100010000011 |
3 | 11122122110200120120110012 |
4 | 103020003013300202003 |
5 | 133013202430424034 |
6 | 2443441535055135 |
7 | 163645612466603 |
oct | 23100307604203 |
9 | 4578420516405 |
10 | 1314312358019 |
11 | 467440075651 |
12 | 1928806714ab |
13 | 96c2934003b |
14 | 47882330c03 |
15 | 242c56a8cce |
hex | 132031f0883 |
1314312358019 has 2 divisors, whose sum is σ = 1314312358020. Its totient is φ = 1314312358018.
The previous prime is 1314312358003. The next prime is 1314312358049. The reversal of 1314312358019 is 9108532134131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9108532134131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314312358019 - 24 = 1314312358003 is a prime.
It is a super-2 number, since 2×13143123580192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314312358049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657156179009 + 657156179010.
It is an arithmetic number, because the mean of its divisors is an integer number (657156179010).
Almost surely, 21314312358019 is an apocalyptic number.
1314312358019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314312358019 is an equidigital number, since it uses as much as digits as its factorization.
1314312358019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 41.
The spelling of 1314312358019 in words is "one trillion, three hundred fourteen billion, three hundred twelve million, three hundred fifty-eight thousand, nineteen".
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