Base | Representation |
---|---|
bin | 11101111000100110101101… |
… | …110111000010011101010001 |
3 | 122020100220002110120100011001 |
4 | 131320212231313002131101 |
5 | 114211400204021024444 |
6 | 1143311330022022001 |
7 | 36453510332145655 |
oct | 3570465567023521 |
9 | 566326073510131 |
10 | 131433211111249 |
11 | 3897356a2409a3 |
12 | 128a8778577901 |
13 | 58451388b3278 |
14 | 2465589490a65 |
15 | 102dd2d1c78d4 |
hex | 7789addc2751 |
131433211111249 has 2 divisors, whose sum is σ = 131433211111250. Its totient is φ = 131433211111248.
The previous prime is 131433211111199. The next prime is 131433211111289. The reversal of 131433211111249 is 942111112334131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92624609692224 + 38808601419025 = 9624168^2 + 6229655^2 .
It is a cyclic number.
It is not a de Polignac number, because 131433211111249 - 29 = 131433211110737 is a prime.
It is not a weakly prime, because it can be changed into another prime (131433211111289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716605555624 + 65716605555625.
It is an arithmetic number, because the mean of its divisors is an integer number (65716605555625).
Almost surely, 2131433211111249 is an apocalyptic number.
It is an amenable number.
131433211111249 is a deficient number, since it is larger than the sum of its proper divisors (1).
131433211111249 is an equidigital number, since it uses as much as digits as its factorization.
131433211111249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 37.
The spelling of 131433211111249 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, two hundred eleven million, one hundred eleven thousand, two hundred forty-nine".
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