Base | Representation |
---|---|
bin | 1011111101000010101111… |
… | …0000011001001101111011 |
3 | 1201112111020112202210110122 |
4 | 2333100223300121031323 |
5 | 3210320022003013001 |
6 | 43541544142203455 |
7 | 2524401032644343 |
oct | 277205360311573 |
9 | 51474215683418 |
10 | 13143334032251 |
11 | 4208069462695 |
12 | 1583323b8358b |
13 | 7445461b6b57 |
14 | 3361d836bd23 |
15 | 17bd4ce2eb1b |
hex | bf42bc1937b |
13143334032251 has 2 divisors, whose sum is σ = 13143334032252. Its totient is φ = 13143334032250.
The previous prime is 13143334032247. The next prime is 13143334032277. The reversal of 13143334032251 is 15223043334131.
It is a weak prime.
It is an emirp because it is prime and its reverse (15223043334131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13143334032251 - 22 = 13143334032247 is a prime.
It is not a weakly prime, because it can be changed into another prime (13143334038251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571667016125 + 6571667016126.
It is an arithmetic number, because the mean of its divisors is an integer number (6571667016126).
Almost surely, 213143334032251 is an apocalyptic number.
13143334032251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143334032251 is an equidigital number, since it uses as much as digits as its factorization.
13143334032251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 13143334032251 its reverse (15223043334131), we get a palindrome (28366377366382).
The spelling of 13143334032251 in words is "thirteen trillion, one hundred forty-three billion, three hundred thirty-four million, thirty-two thousand, two hundred fifty-one".
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