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13143420131 is a prime number
BaseRepresentation
bin11000011110110100…
…01010110011100011
31020220222122220220012
430033122022303203
5203404203421011
610012113035135
7643464141062
oct141732126343
936828586805
1013143420131
115635133096
122669855aab
13131600899a
148c98201d9
1551dd31a8b
hex30f68ace3

13143420131 has 2 divisors, whose sum is σ = 13143420132. Its totient is φ = 13143420130.

The previous prime is 13143420109. The next prime is 13143420151. The reversal of 13143420131 is 13102434131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13143420131 - 226 = 13076311267 is a prime.

It is a super-2 number, since 2×131434201312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13143420097 and 13143420106.

It is not a weakly prime, because it can be changed into another prime (13143420151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571710065 + 6571710066.

It is an arithmetic number, because the mean of its divisors is an integer number (6571710066).

Almost surely, 213143420131 is an apocalyptic number.

13143420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143420131 is an equidigital number, since it uses as much as digits as its factorization.

13143420131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13143420131 its reverse (13102434131), we get a palindrome (26245854262).

The spelling of 13143420131 in words is "thirteen billion, one hundred forty-three million, four hundred twenty thousand, one hundred thirty-one".