Base | Representation |
---|---|
bin | 11101111000100111101010… |
… | …110011001010011010000011 |
3 | 122020100222201201101100021111 |
4 | 131320213222303022122003 |
5 | 114211404302234133121 |
6 | 1143312015303304151 |
7 | 36453544555306654 |
oct | 3570475263123203 |
9 | 566328651340244 |
10 | 131434233505411 |
11 | 38973a4436a851 |
12 | 128a8a02a4b057 |
13 | 584526c661525 |
14 | 246564518b52b |
15 | 102dd8cd2e2e1 |
hex | 7789eacca683 |
131434233505411 has 2 divisors, whose sum is σ = 131434233505412. Its totient is φ = 131434233505410.
The previous prime is 131434233505381. The next prime is 131434233505469. The reversal of 131434233505411 is 114505332434131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131434233505411 - 213 = 131434233497219 is a prime.
It is not a weakly prime, because it can be changed into another prime (131434233505481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65717116752705 + 65717116752706.
It is an arithmetic number, because the mean of its divisors is an integer number (65717116752706).
Almost surely, 2131434233505411 is an apocalyptic number.
131434233505411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131434233505411 is an equidigital number, since it uses as much as digits as its factorization.
131434233505411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 131434233505411 its reverse (114505332434131), we get a palindrome (245939565939542).
The spelling of 131434233505411 in words is "one hundred thirty-one trillion, four hundred thirty-four billion, two hundred thirty-three million, five hundred five thousand, four hundred eleven".
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