13143440441 has 2 divisors, whose sum is σ = 13143440442. Its totient is φ = 13143440440.

The previous prime is 13143440411. The next prime is 13143440447. The reversal of 13143440441 is 14404434131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12148668841 + 994771600 = 110221^2 + 31540^2 .

It is an emirp because it is prime and its reverse (14404434131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13143440441 - 2¹⁸ = 13143178297 is a prime.

It is a super-2 number, since 2×13143440441² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13143440447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571720220 + 6571720221.

It is an arithmetic number, because the mean of its divisors is an integer number (6571720221).

Almost surely, 2^13143440441 is an apocalyptic number.

It is an amenable number.

13143440441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143440441 is an equidigital number, since it uses as much as digits as its factorization.

13143440441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 13143440441 its reverse (14404434131), we get a palindrome (27547874572).

The spelling of 13143440441 in words is "thirteen billion, one hundred forty-three million, four hundred forty thousand, four hundred forty-one".