Base | Representation |
---|---|
bin | 111101001101001101… |
… | …1011100001011100001 |
3 | 110120021021100220211111 |
4 | 1322122123130023201 |
5 | 4123142103402312 |
6 | 140214353143321 |
7 | 12332126513422 |
oct | 1723233341341 |
9 | 416237326744 |
10 | 131439903457 |
11 | 5081a442995 |
12 | 21582b5ab41 |
13 | c5192b4c05 |
14 | 650c807649 |
15 | 364448b8a7 |
hex | 1e9a6dc2e1 |
131439903457 has 2 divisors, whose sum is σ = 131439903458. Its totient is φ = 131439903456.
The previous prime is 131439903433. The next prime is 131439903461. The reversal of 131439903457 is 754309934131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74395835536 + 57044067921 = 272756^2 + 238839^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131439903457 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131439903457.
It is not a weakly prime, because it can be changed into another prime (131439903557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65719951728 + 65719951729.
It is an arithmetic number, because the mean of its divisors is an integer number (65719951729).
Almost surely, 2131439903457 is an apocalyptic number.
It is an amenable number.
131439903457 is a deficient number, since it is larger than the sum of its proper divisors (1).
131439903457 is an equidigital number, since it uses as much as digits as its factorization.
131439903457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 131439903457 in words is "one hundred thirty-one billion, four hundred thirty-nine million, nine hundred three thousand, four hundred fifty-seven".
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