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1314400130043 = 3711132337895779
BaseRepresentation
bin10011001000001000010…
…110100101001111111011
311122122200210201212000220
4103020020112211033323
5133013342413130133
62443454352231123
7163651026522660
oct23101026451773
94578623655026
101314400130043
11467485675010
121928a5b3b4a3
1396c41591b50
144788dc5ba67
15242cd2455b3
hex132085a53fb

1314400130043 has 256 divisors, whose sum is σ = 2550494822400. Its totient is φ = 579893022720.

The previous prime is 1314400130041. The next prime is 1314400130159. The reversal of 1314400130043 is 3400310044131.

It is not a de Polignac number, because 1314400130043 - 21 = 1314400130041 is a prime.

It is a super-2 number, since 2×13144001300432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314400129995 and 1314400130022.

It is not an unprimeable number, because it can be changed into a prime (1314400130041) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 227441328 + ... + 227447106.

It is an arithmetic number, because the mean of its divisors is an integer number (9962870400).

Almost surely, 21314400130043 is an apocalyptic number.

1314400130043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1314400130043 is a deficient number, since it is larger than the sum of its proper divisors (1236094692357).

1314400130043 is a wasteful number, since it uses less digits than its factorization.

1314400130043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5962.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 1314400130043 its reverse (3400310044131), we get a palindrome (4714710174174).

The spelling of 1314400130043 in words is "one trillion, three hundred fourteen billion, four hundred million, one hundred thirty thousand, forty-three".