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131440444034353 is a prime number
BaseRepresentation
bin11101111000101101011100…
…111110011100110100110001
3122020101120202112120220100221
4131320231130332130310301
5114212010012133044403
61143314523440413041
736454154510034226
oct3570553476346461
9566346675526327
10131440444034353
11389766410150a3
12128aa056917181
135845a1c22cb1c
142465a73d1d94d
15102e1031a0dbd
hex778b5cf9cd31

131440444034353 has 2 divisors, whose sum is σ = 131440444034354. Its totient is φ = 131440444034352.

The previous prime is 131440444034329. The next prime is 131440444034399. The reversal of 131440444034353 is 353430444044131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126207092361249 + 5233351673104 = 11234193^2 + 2287652^2 .

It is a cyclic number.

It is not a de Polignac number, because 131440444034353 - 25 = 131440444034321 is a prime.

It is not a weakly prime, because it can be changed into another prime (131440444034323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720222017176 + 65720222017177.

It is an arithmetic number, because the mean of its divisors is an integer number (65720222017177).

Almost surely, 2131440444034353 is an apocalyptic number.

It is an amenable number.

131440444034353 is a deficient number, since it is larger than the sum of its proper divisors (1).

131440444034353 is an equidigital number, since it uses as much as digits as its factorization.

131440444034353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1658880, while the sum is 43.

Adding to 131440444034353 its reverse (353430444044131), we get a palindrome (484870888078484).

The spelling of 131440444034353 in words is "one hundred thirty-one trillion, four hundred forty billion, four hundred forty-four million, thirty-four thousand, three hundred fifty-three".