Base | Representation |
---|---|
bin | 111101001101001110… |
… | …1101001101101100011 |
3 | 110120021022110101001101 |
4 | 1322122131221231203 |
5 | 4123142230430141 |
6 | 140214413415231 |
7 | 12332134446514 |
oct | 1723235515543 |
9 | 416238411041 |
10 | 131440483171 |
11 | 5081a7a9498 |
12 | 2158319a517 |
13 | c519458a3a |
14 | 650c918a0b |
15 | 3644553531 |
hex | 1e9a769b63 |
131440483171 has 2 divisors, whose sum is σ = 131440483172. Its totient is φ = 131440483170.
The previous prime is 131440483067. The next prime is 131440483199. The reversal of 131440483171 is 171384044131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131440483171 - 225 = 131406928739 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131440483171.
It is not a weakly prime, because it can be changed into another prime (131440483271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720241585 + 65720241586.
It is an arithmetic number, because the mean of its divisors is an integer number (65720241586).
Almost surely, 2131440483171 is an apocalyptic number.
131440483171 is a deficient number, since it is larger than the sum of its proper divisors (1).
131440483171 is an equidigital number, since it uses as much as digits as its factorization.
131440483171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 37.
The spelling of 131440483171 in words is "one hundred thirty-one billion, four hundred forty million, four hundred eighty-three thousand, one hundred seventy-one".
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