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131441101444313 is a prime number
BaseRepresentation
bin11101111000101110000100…
…001010010001010011011001
3122020101122110100121210021222
4131320232010022101103121
5114212012333432204223
61143315113003141425
736454210011652313
oct3570560412212331
9566348410553258
10131441101444313
1138976949114a11
12128aa1bab14875
135845ac54a97bb
142465ad736c7b3
15102e140c5e0c8
hex778b842914d9

131441101444313 has 2 divisors, whose sum is σ = 131441101444314. Its totient is φ = 131441101444312.

The previous prime is 131441101444249. The next prime is 131441101444369. The reversal of 131441101444313 is 313444101144131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83792274131344 + 47648827312969 = 9153812^2 + 6902813^2 .

It is a cyclic number.

It is not a de Polignac number, because 131441101444313 - 26 = 131441101444249 is a prime.

It is a super-3 number, since 3×1314411014443133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (131441107444313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720550722156 + 65720550722157.

It is an arithmetic number, because the mean of its divisors is an integer number (65720550722157).

Almost surely, 2131441101444313 is an apocalyptic number.

It is an amenable number.

131441101444313 is a deficient number, since it is larger than the sum of its proper divisors (1).

131441101444313 is an equidigital number, since it uses as much as digits as its factorization.

131441101444313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 131441101444313 its reverse (313444101144131), we get a palindrome (444885202588444).

The spelling of 131441101444313 in words is "one hundred thirty-one trillion, four hundred forty-one billion, one hundred one million, four hundred forty-four thousand, three hundred thirteen".