Base | Representation |
---|---|
bin | 10011001000001010001… |
… | …001101101101001100101 |
3 | 11122122202220112012112121 |
4 | 103020022021231221211 |
5 | 133013423124423023 |
6 | 2443501351145541 |
7 | 163651544204101 |
oct | 23101211555145 |
9 | 4578686465477 |
10 | 1314430311013 |
11 | 4674a0709466 |
12 | 1928b40752b1 |
13 | 96c478cb301 |
14 | 47893c76901 |
15 | 242d0c07d5d |
hex | 1320a26da65 |
1314430311013 has 4 divisors (see below), whose sum is σ = 1314436813900. Its totient is φ = 1314423808128.
The previous prime is 1314430310989. The next prime is 1314430311109. The reversal of 1314430311013 is 3101130344131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 20153209444 + 1294277101569 = 141962^2 + 1137663^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314430311013 - 213 = 1314430302821 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314430311113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2938188 + ... + 3355861.
It is an arithmetic number, because the mean of its divisors is an integer number (328609203475).
Almost surely, 21314430311013 is an apocalyptic number.
It is an amenable number.
1314430311013 is a deficient number, since it is larger than the sum of its proper divisors (6502887).
1314430311013 is an equidigital number, since it uses as much as digits as its factorization.
1314430311013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6502886.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1314430311013 its reverse (3101130344131), we get a palindrome (4415560655144).
The spelling of 1314430311013 in words is "one trillion, three hundred fourteen billion, four hundred thirty million, three hundred eleven thousand, thirteen".
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