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13144324123200 = 2635219144126361
BaseRepresentation
bin1011111101000110011011…
…0001010010101001000000
31201112120210112210121220210
42333101212301102221000
53210324033433420300
643542230311234120
72524434414405024
oct277214661225100
951476715717823
1013144324123200
114208527328676
12158355b678940
1374467336499a
1433628da5a384
1517bda9d05050
hexbf466c52a40

13144324123200 has 168 divisors, whose sum is σ = 45394038975520. Its totient is φ = 3320671334400.

The previous prime is 13144324123187. The next prime is 13144324123211. The reversal of 13144324123200 is 232142344131.

It is a super-3 number, since 3×131443241232003 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 71971981 + ... + 72154380.

Almost surely, 213144324123200 is an apocalyptic number.

13144324123200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13144324123200 is an abundant number, since it is smaller than the sum of its proper divisors (32249714852320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13144324123200 is a wasteful number, since it uses less digits than its factorization.

13144324123200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144126405 (or 144126390 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 13144324123200 its reverse (232142344131), we get a palindrome (13376466467331).

The spelling of 13144324123200 in words is "thirteen trillion, one hundred forty-four billion, three hundred twenty-four million, one hundred twenty-three thousand, two hundred".