Base | Representation |
---|---|
bin | 11000011110111011… |
… | …01001011011101011 |
3 | 1020221001101020202112 |
4 | 30033131221123223 |
5 | 203404422111021 |
6 | 10012144352535 |
7 | 643504656446 |
oct | 141735513353 |
9 | 36831336675 |
10 | 13144332011 |
11 | 56356a6208 |
12 | 266a01574b |
13 | 1316267a65 |
14 | 8c99ba65d |
15 | 51de61d5b |
hex | 30f7696eb |
13144332011 has 2 divisors, whose sum is σ = 13144332012. Its totient is φ = 13144332010.
The previous prime is 13144331999. The next prime is 13144332037. The reversal of 13144332011 is 11023344131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13144332011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13144332611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572166005 + 6572166006.
It is an arithmetic number, because the mean of its divisors is an integer number (6572166006).
Almost surely, 213144332011 is an apocalyptic number.
13144332011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144332011 is an equidigital number, since it uses as much as digits as its factorization.
13144332011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13144332011 its reverse (11023344131), we get a palindrome (24167676142).
The spelling of 13144332011 in words is "thirteen billion, one hundred forty-four million, three hundred thirty-two thousand, eleven".
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