Base | Representation |
---|---|
bin | 111101001101010101… |
… | …1000100110101001001 |
3 | 110120021120002011010212 |
4 | 1322122223010311021 |
5 | 4123144131031441 |
6 | 140215021050505 |
7 | 12332206404035 |
oct | 1723253046511 |
9 | 416246064125 |
10 | 131444002121 |
11 | 50821792313 |
12 | 215843b6a35 |
13 | c51a0bb663 |
14 | 650d1931c5 |
15 | 36449eaeeb |
hex | 1e9aac4d49 |
131444002121 has 2 divisors, whose sum is σ = 131444002122. Its totient is φ = 131444002120.
The previous prime is 131444002103. The next prime is 131444002141. The reversal of 131444002121 is 121200444131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131287376896 + 156625225 = 362336^2 + 12515^2 .
It is a cyclic number.
It is not a de Polignac number, because 131444002121 - 226 = 131376893257 is a prime.
It is not a weakly prime, because it can be changed into another prime (131444002141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65722001060 + 65722001061.
It is an arithmetic number, because the mean of its divisors is an integer number (65722001061).
Almost surely, 2131444002121 is an apocalyptic number.
It is an amenable number.
131444002121 is a deficient number, since it is larger than the sum of its proper divisors (1).
131444002121 is an equidigital number, since it uses as much as digits as its factorization.
131444002121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 131444002121 its reverse (121200444131), we get a palindrome (252644446252).
The spelling of 131444002121 in words is "one hundred thirty-one billion, four hundred forty-four million, two thousand, one hundred twenty-one".
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