Base | Representation |
---|---|
bin | 10011001000001010110… |
… | …111100001100111110011 |
3 | 11122122210202010100021122 |
4 | 103020022313201213303 |
5 | 133013434213222441 |
6 | 2443502500412455 |
7 | 163652051242565 |
oct | 23101267414763 |
9 | 4578722110248 |
10 | 1314442320371 |
11 | 4674a7471254 |
12 | 1928b80a712b |
13 | 96c4a24463b |
14 | 478956c1335 |
15 | 242d1ccb34b |
hex | 1320ade19f3 |
1314442320371 has 2 divisors, whose sum is σ = 1314442320372. Its totient is φ = 1314442320370.
The previous prime is 1314442320361. The next prime is 1314442320439. The reversal of 1314442320371 is 1730232444131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314442320371 - 210 = 1314442319347 is a prime.
It is a super-2 number, since 2×13144423203712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314442320361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657221160185 + 657221160186.
It is an arithmetic number, because the mean of its divisors is an integer number (657221160186).
Almost surely, 21314442320371 is an apocalyptic number.
1314442320371 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314442320371 is an equidigital number, since it uses as much as digits as its factorization.
1314442320371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 1314442320371 in words is "one trillion, three hundred fourteen billion, four hundred forty-two million, three hundred twenty thousand, three hundred seventy-one".
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