Base | Representation |
---|---|
bin | 111101001101010101… |
… | …1111100111101101001 |
3 | 110120021120111211112102 |
4 | 1322122223330331221 |
5 | 4123144210411131 |
6 | 140215030023145 |
7 | 12332211352253 |
oct | 1723253747551 |
9 | 416246454472 |
10 | 131444232041 |
11 | 5082192a031 |
12 | 215844a7ab5 |
13 | c51a16c1c5 |
14 | 650d212cd3 |
15 | 3644a441cb |
hex | 1e9aafcf69 |
131444232041 has 2 divisors, whose sum is σ = 131444232042. Its totient is φ = 131444232040.
The previous prime is 131444232019. The next prime is 131444232047. The reversal of 131444232041 is 140232444131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123344952025 + 8099280016 = 351205^2 + 89996^2 .
It is a cyclic number.
It is not a de Polignac number, because 131444232041 - 26 = 131444231977 is a prime.
It is a super-2 number, since 2×1314442320412 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131444231995 and 131444232013.
It is not a weakly prime, because it can be changed into another prime (131444232047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65722116020 + 65722116021.
It is an arithmetic number, because the mean of its divisors is an integer number (65722116021).
Almost surely, 2131444232041 is an apocalyptic number.
It is an amenable number.
131444232041 is a deficient number, since it is larger than the sum of its proper divisors (1).
131444232041 is an equidigital number, since it uses as much as digits as its factorization.
131444232041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 131444232041 its reverse (140232444131), we get a palindrome (271676676172).
The spelling of 131444232041 in words is "one hundred thirty-one billion, four hundred forty-four million, two hundred thirty-two thousand, forty-one".
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