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131444273641 is a prime number
BaseRepresentation
bin111101001101010110…
…0000111000111101001
3110120021120120221121011
41322122230013013221
54123144213224031
6140215030543521
712332211614452
oct1723254070751
9416246527534
10131444273641
115082195830a
1221584507ba1
13c51a185115
14650d224129
153644a516b1
hex1e9ab071e9

131444273641 has 2 divisors, whose sum is σ = 131444273642. Its totient is φ = 131444273640.

The previous prime is 131444273627. The next prime is 131444273663. The reversal of 131444273641 is 146372444131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124013144025 + 7431129616 = 352155^2 + 86204^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131444273641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131444273594 and 131444273603.

It is not a weakly prime, because it can be changed into another prime (131444270641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65722136820 + 65722136821.

It is an arithmetic number, because the mean of its divisors is an integer number (65722136821).

Almost surely, 2131444273641 is an apocalyptic number.

It is an amenable number.

131444273641 is a deficient number, since it is larger than the sum of its proper divisors (1).

131444273641 is an equidigital number, since it uses as much as digits as its factorization.

131444273641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 193536, while the sum is 40.

The spelling of 131444273641 in words is "one hundred thirty-one billion, four hundred forty-four million, two hundred seventy-three thousand, six hundred forty-one".