13144434152501 has 4 divisors (see below), whose sum is σ = 13274577065004. Its totient is φ = 13014291240000.

The previous prime is 13144434152459. The next prime is 13144434152527. The reversal of 13144434152501 is 10525143444131.

13144434152501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12436724177476 + 707709975025 = 3526574^2 + 841255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13144434152501 is a prime.

It is a super-2 number, since 2×13144434152501² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13144434142501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65071456100 + ... + 65071456301.

It is an arithmetic number, because the mean of its divisors is an integer number (3318644266251).

Almost surely, 2^{13144434152501} is an apocalyptic number.

It is an amenable number.

13144434152501 is a deficient number, since it is larger than the sum of its proper divisors (130142912503).

13144434152501 is a wasteful number, since it uses less digits than its factorization.

13144434152501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130142912502.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 13144434152501 its reverse (10525143444131), we get a palindrome (23669577596632).

The spelling of 13144434152501 in words is "thirteen trillion, one hundred forty-four billion, four hundred thirty-four million, one hundred fifty-two thousand, five hundred one".