Base | Representation |
---|---|
bin | 11000011110111100… |
… | …00100011011100001 |
3 | 1020221001120212110011 |
4 | 30033132010123201 |
5 | 203404434130333 |
6 | 10012151004521 |
7 | 643505630032 |
oct | 141736043341 |
9 | 36831525404 |
10 | 13144442593 |
11 | 56357712a7 |
12 | 266a069741 |
13 | 13162a61a9 |
14 | 8c9a08a89 |
15 | 51de849cd |
hex | 30f7846e1 |
13144442593 has 2 divisors, whose sum is σ = 13144442594. Its totient is φ = 13144442592.
The previous prime is 13144442581. The next prime is 13144442621. The reversal of 13144442593 is 39524444131.
13144442593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12585025489 + 559417104 = 112183^2 + 23652^2 .
It is an emirp because it is prime and its reverse (39524444131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13144442593 - 29 = 13144442081 is a prime.
It is not a weakly prime, because it can be changed into another prime (13144442533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572221296 + 6572221297.
It is an arithmetic number, because the mean of its divisors is an integer number (6572221297).
Almost surely, 213144442593 is an apocalyptic number.
It is an amenable number.
13144442593 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144442593 is an equidigital number, since it uses as much as digits as its factorization.
13144442593 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 207360, while the sum is 40.
The spelling of 13144442593 in words is "thirteen billion, one hundred forty-four million, four hundred forty-two thousand, five hundred ninety-three".
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