Base | Representation |
---|---|
bin | 1011111101000111001100… |
… | …0110111011101110111110 |
3 | 1201112121022222022022110000 |
4 | 2333101303012323232332 |
5 | 3210324444431420014 |
6 | 43542303024055130 |
7 | 2524442510025255 |
oct | 277216306735676 |
9 | 51477288268400 |
10 | 13144531123134 |
11 | 42086231617a4 |
12 | 15835b8a644a6 |
13 | 7446a7200158 |
14 | 3362ad34179c |
15 | 17bdbd093509 |
hex | bf4731bbbbe |
13144531123134 has 20 divisors (see below), whose sum is σ = 29453486405904. Its totient is φ = 4381510374324.
The previous prime is 13144531123121. The next prime is 13144531123189. The reversal of 13144531123134 is 43132113544131.
13144531123134 is a `hidden beast` number, since 1 + 31 + 4 + 453 + 112 + 31 + 34 = 666.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 40569540342 + ... + 40569540665.
Almost surely, 213144531123134 is an apocalyptic number.
13144531123134 is an abundant number, since it is smaller than the sum of its proper divisors (16308955282770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13144531123134 is an equidigital number, since it uses as much as digits as its factorization.
13144531123134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81139081021 (or 81139081012 counting only the distinct ones).
The product of its digits is 51840, while the sum is 36.
Adding to 13144531123134 its reverse (43132113544131), we get a palindrome (56276644667265).
The spelling of 13144531123134 in words is "thirteen trillion, one hundred forty-four billion, five hundred thirty-one million, one hundred twenty-three thousand, one hundred thirty-four".
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