Base | Representation |
---|---|
bin | 10011001000001110010… |
… | …100110111001001001111 |
3 | 11122122221210022011110212 |
4 | 103020032110313021033 |
5 | 133014044041423401 |
6 | 2443512332153035 |
7 | 163653354361100 |
oct | 23101624671117 |
9 | 4578853264425 |
10 | 1314500342351 |
11 | 4675271a0aa9 |
12 | 19291360877b |
13 | 96c5927b181 |
14 | 4789d2a63a7 |
15 | 242d6e3cdbb |
hex | 1320e53724f |
1314500342351 has 6 divisors (see below), whose sum is σ = 1529112643200. Its totient is φ = 1126714579116.
The previous prime is 1314500342327. The next prime is 1314500342357. The reversal of 1314500342351 is 1532430054131.
It is not a de Polignac number, because 1314500342351 - 214 = 1314500325967 is a prime.
It is a super-2 number, since 2×13145003423512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314500342357) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13413268751 + ... + 13413268848.
It is an arithmetic number, because the mean of its divisors is an integer number (254852107200).
Almost surely, 21314500342351 is an apocalyptic number.
1314500342351 is a deficient number, since it is larger than the sum of its proper divisors (214612300849).
1314500342351 is an equidigital number, since it uses as much as digits as its factorization.
1314500342351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26826537613 (or 26826537606 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1314500342351 its reverse (1532430054131), we get a palindrome (2846930396482).
The spelling of 1314500342351 in words is "one trillion, three hundred fourteen billion, five hundred million, three hundred forty-two thousand, three hundred fifty-one".
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