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13145004153 = 324333966419
BaseRepresentation
bin11000011111000000…
…01101100001111001
31020221002122101202200
430033200031201321
5203410110113103
610012211020413
7643513456161
oct141740154171
936832571680
1013145004153
1156360151a6
12266a29a709
131316441988
148c9b135a1
1551e0460a3
hex30f80d879

13145004153 has 12 divisors (see below), whose sum is σ = 19428792240. Its totient is φ = 8559537336.

The previous prime is 13145004151. The next prime is 13145004167. The reversal of 13145004153 is 35140054131.

It is a happy number.

13145004153 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 500 + 4 + 153 = 666.

It is not a de Polignac number, because 13145004153 - 21 = 13145004151 is a prime.

It is a super-2 number, since 2×131450041532 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13145004151) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16982823 + ... + 16983596.

It is an arithmetic number, because the mean of its divisors is an integer number (1619066020).

Almost surely, 213145004153 is an apocalyptic number.

It is an amenable number.

13145004153 is a deficient number, since it is larger than the sum of its proper divisors (6283788087).

13145004153 is a wasteful number, since it uses less digits than its factorization.

13145004153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33966468 (or 33966465 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 13145004153 its reverse (35140054131), we get a palindrome (48285058284).

The spelling of 13145004153 in words is "thirteen billion, one hundred forty-five million, four thousand, one hundred fifty-three".

Divisors: 1 3 9 43 129 387 33966419 101899257 305697771 1460556017 4381668051 13145004153