Base | Representation |
---|---|
bin | 10011001000010000001… |
… | …101110000011110001001 |
3 | 11122200000222221021211222 |
4 | 103020100031300132021 |
5 | 133014130200100231 |
6 | 2443515423331425 |
7 | 163654220634623 |
oct | 23102015603611 |
9 | 4580028837758 |
10 | 1314532034441 |
11 | 46754307780a |
12 | 192922150b75 |
13 | 96c629c63a2 |
14 | 478a3595c13 |
15 | 242d9aed27b |
hex | 13210370789 |
1314532034441 has 2 divisors, whose sum is σ = 1314532034442. Its totient is φ = 1314532034440.
The previous prime is 1314532034423. The next prime is 1314532034449. The reversal of 1314532034441 is 1444302354131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 994397868025 + 320134166416 = 997195^2 + 565804^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314532034441 - 230 = 1313458292617 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314532034449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657266017220 + 657266017221.
It is an arithmetic number, because the mean of its divisors is an integer number (657266017221).
Almost surely, 21314532034441 is an apocalyptic number.
It is an amenable number.
1314532034441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314532034441 is an equidigital number, since it uses as much as digits as its factorization.
1314532034441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 1314532034441 its reverse (1444302354131), we get a palindrome (2758834388572).
The spelling of 1314532034441 in words is "one trillion, three hundred fourteen billion, five hundred thirty-two million, thirty-four thousand, four hundred forty-one".
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