Base | Representation |
---|---|
bin | 10011001000010001111… |
… | …101011100010000000011 |
3 | 11122200010001000201202122 |
4 | 103020101331130100003 |
5 | 133014210143433442 |
6 | 2443522351034455 |
7 | 163655024533325 |
oct | 23102175342003 |
9 | 4580101021678 |
10 | 1314561311747 |
11 | 467558654232 |
12 | 19292bb0ba2b |
13 | 96c68aa7438 |
14 | 478a7417615 |
15 | 242dc482dd2 |
hex | 13211f5c403 |
1314561311747 has 2 divisors, whose sum is σ = 1314561311748. Its totient is φ = 1314561311746.
The previous prime is 1314561311729. The next prime is 1314561311783. The reversal of 1314561311747 is 7471131654131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314561311747 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314561311698 and 1314561311707.
It is not a weakly prime, because it can be changed into another prime (1314561311347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657280655873 + 657280655874.
It is an arithmetic number, because the mean of its divisors is an integer number (657280655874).
Almost surely, 21314561311747 is an apocalyptic number.
1314561311747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314561311747 is an equidigital number, since it uses as much as digits as its factorization.
1314561311747 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 211680, while the sum is 44.
Adding to 1314561311747 its reverse (7471131654131), we get a palindrome (8785692965878).
The spelling of 1314561311747 in words is "one trillion, three hundred fourteen billion, five hundred sixty-one million, three hundred eleven thousand, seven hundred forty-seven".
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