Base | Representation |
---|---|
bin | 10011001000100011100… |
… | …101110100111010101001 |
3 | 11122200212122121220100021 |
4 | 103020203211310322221 |
5 | 133020311410024314 |
6 | 2444011555040441 |
7 | 163665246016405 |
oct | 23104345647251 |
9 | 4580778556307 |
10 | 1314857111209 |
11 | 46769a6197a4 |
12 | 1929b2ba0121 |
13 | 96cb51642c5 |
14 | 478d4816105 |
15 | 24308412324 |
hex | 13223974ea9 |
1314857111209 has 2 divisors, whose sum is σ = 1314857111210. Its totient is φ = 1314857111208.
The previous prime is 1314857111159. The next prime is 1314857111231. The reversal of 1314857111209 is 9021117584131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 675092289600 + 639764821609 = 821640^2 + 799853^2 .
It is an emirp because it is prime and its reverse (9021117584131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314857111209 - 231 = 1312709627561 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314857411209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657428555604 + 657428555605.
It is an arithmetic number, because the mean of its divisors is an integer number (657428555605).
Almost surely, 21314857111209 is an apocalyptic number.
It is an amenable number.
1314857111209 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314857111209 is an equidigital number, since it uses as much as digits as its factorization.
1314857111209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 43.
The spelling of 1314857111209 in words is "one trillion, three hundred fourteen billion, eight hundred fifty-seven million, one hundred eleven thousand, two hundred nine".
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