Base | Representation |
---|---|
bin | 111101001110101000… |
… | …1001100111011100011 |
3 | 110120101121000200020211 |
4 | 1322131101030323203 |
5 | 4123241303114303 |
6 | 140223214314551 |
7 | 12333245513221 |
oct | 1723521147343 |
9 | 416347020224 |
10 | 131487551203 |
11 | 50844327398 |
12 | 21596ab8a57 |
13 | c526128748 |
14 | 6514c8bb11 |
15 | 364874e66d |
hex | 1e9d44cee3 |
131487551203 has 2 divisors, whose sum is σ = 131487551204. Its totient is φ = 131487551202.
The previous prime is 131487551197. The next prime is 131487551249. The reversal of 131487551203 is 302155784131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131487551203 - 217 = 131487420131 is a prime.
It is a super-2 number, since 2×1314875512032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131487051203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65743775601 + 65743775602.
It is an arithmetic number, because the mean of its divisors is an integer number (65743775602).
Almost surely, 2131487551203 is an apocalyptic number.
131487551203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131487551203 is an equidigital number, since it uses as much as digits as its factorization.
131487551203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 40.
The spelling of 131487551203 in words is "one hundred thirty-one billion, four hundred eighty-seven million, five hundred fifty-one thousand, two hundred three".
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