Base | Representation |
---|---|
bin | 111101001110101010… |
… | …0111101011100100001 |
3 | 110120101122212201121212 |
4 | 1322131110331130201 |
5 | 4123242031130403 |
6 | 140223251355505 |
7 | 12333260055326 |
oct | 1723524753441 |
9 | 416348781555 |
10 | 131488536353 |
11 | 5084493a569 |
12 | 215972b2b95 |
13 | c5263b1c85 |
14 | 6515066b4d |
15 | 36488964d8 |
hex | 1e9d53d721 |
131488536353 has 2 divisors, whose sum is σ = 131488536354. Its totient is φ = 131488536352.
The previous prime is 131488536341. The next prime is 131488536383. The reversal of 131488536353 is 353635884131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120414552064 + 11073984289 = 347008^2 + 105233^2 .
It is a cyclic number.
It is not a de Polignac number, because 131488536353 - 210 = 131488535329 is a prime.
It is a super-3 number, since 3×1314885363533 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131488536383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65744268176 + 65744268177.
It is an arithmetic number, because the mean of its divisors is an integer number (65744268177).
Almost surely, 2131488536353 is an apocalyptic number.
It is an amenable number.
131488536353 is a deficient number, since it is larger than the sum of its proper divisors (1).
131488536353 is an equidigital number, since it uses as much as digits as its factorization.
131488536353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 50.
The spelling of 131488536353 in words is "one hundred thirty-one billion, four hundred eighty-eight million, five hundred thirty-six thousand, three hundred fifty-three".
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