Base | Representation |
---|---|
bin | 10011001000101100010… |
… | …110010111011100000111 |
3 | 11122201020220010022221021 |
4 | 103020230112113130013 |
5 | 133021112014201010 |
6 | 2444034324332011 |
7 | 164002012012024 |
oct | 23105426273407 |
9 | 4581226108837 |
10 | 1315004053255 |
11 | 467765562502 |
12 | 192a34244007 |
13 | 97009732369 |
14 | 4790a14654b |
15 | 2431628a8da |
hex | 1322c597707 |
1315004053255 has 8 divisors (see below), whose sum is σ = 1661057751600. Its totient is φ = 996634650816.
The previous prime is 1315004053247. The next prime is 1315004053267. The reversal of 1315004053255 is 5523504005131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1315004053255 - 23 = 1315004053247 is a prime.
It is a super-3 number, since 3×13150040532553 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1315004053255.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6921073870 + ... + 6921074059.
It is an arithmetic number, because the mean of its divisors is an integer number (207632218950).
Almost surely, 21315004053255 is an apocalyptic number.
1315004053255 is a deficient number, since it is larger than the sum of its proper divisors (346053698345).
1315004053255 is a wasteful number, since it uses less digits than its factorization.
1315004053255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13842147953.
The product of its (nonzero) digits is 45000, while the sum is 34.
Adding to 1315004053255 its reverse (5523504005131), we get a palindrome (6838508058386).
The spelling of 1315004053255 in words is "one trillion, three hundred fifteen billion, four million, fifty-three thousand, two hundred fifty-five".
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