Base | Representation |
---|---|
bin | 11101111001101001100110… |
… | …010100110100110011110111 |
3 | 122020121202110022211102000001 |
4 | 131321221212110310303313 |
5 | 114214034243000413101 |
6 | 1143404324043332131 |
7 | 36461632056442210 |
oct | 3571514624646367 |
9 | 566552408742001 |
10 | 131505025404151 |
11 | 389a0a7156a093 |
12 | 128ba67ab21047 |
13 | 584bb41b834c9 |
14 | 2468c3d020407 |
15 | 1030b32c16901 |
hex | 779a66534cf7 |
131505025404151 has 16 divisors (see below), whose sum is σ = 157076745618240. Its totient is φ = 107709768391680.
The previous prime is 131505025404149. The next prime is 131505025404157. The reversal of 131505025404151 is 151404520505131.
It is not a de Polignac number, because 131505025404151 - 21 = 131505025404149 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131505025404151.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131505025404157) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3339196840 + ... + 3339236221.
It is an arithmetic number, because the mean of its divisors is an integer number (9817296601140).
Almost surely, 2131505025404151 is an apocalyptic number.
131505025404151 is a deficient number, since it is larger than the sum of its proper divisors (25571720214089).
131505025404151 is an equidigital number, since it uses as much as digits as its factorization.
131505025404151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6678433194.
The product of its (nonzero) digits is 60000, while the sum is 37.
Adding to 131505025404151 its reverse (151404520505131), we get a palindrome (282909545909282).
The spelling of 131505025404151 in words is "one hundred thirty-one trillion, five hundred five billion, twenty-five million, four hundred four thousand, one hundred fifty-one".
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